Get Answers to all your Questions

header-bg qa

The density of a crystal is found to be2.16 g/cm^{3}. If the lattice parameter of the crystal is 3.6 \AA, what is the atomic mass of the substance?

 

Option: 1

24.64 g/mol


Option: 2

48.45 g/mol


Option: 3

16.32 g/mol


Option: 4

72.89 g/mol


Answers (1)

best_answer

The volume of the unit cell of the crystal can be calculated as (3.6 \AA)3 = 46.656 \AA 3. The number of atoms in the unit cell can be calculated as (2.16 g/cm^{3})/(48.045 g/mol \times 6.023 \times 10^{23} mol^{-1} \times (46.656 \times 10^{-24} cm^{3})) = 1. .The atomic mass of the substance can be calculated as (2.16 g/cm^{3})/(46.656 \times 10^{-24} cm^{3}) = 48.045 g/mol.

 

Posted by

Rishi

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks