Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The diffraction of a crystal of Barium with X-ray of wavelength 2.29  gives a fi

The diffraction of a crystal of Barium with X-ray of wavelength 2.29 \small \AA gives a first order reflection at \small 27^{\circ}8' . What is the distance (in \AA) between the diffracting planes ?

Option: 1

1.46


Option: 2

1.5


Option: 3

2.51


Option: 4

5.46


Answers (1)

best_answer

Bragg’s Equation

This equation gives a simple relationship between the wavelength Of X-rays and the distance between the planes in the crystal and the angle Of reflection. This equation can be written as: 

\\\mathrm{n} \lambda=2 \mathrm{d} \sin \theta\\\\ \mathrm{Here} \\\mathrm{n\:=\:Order\:of\:reflection;\:in\:general\:it\:is\:taken\:as\:1.}\\\\\mathrm{\lambda\: =\:Wavelength\:of\:X-rays}\\\\\mathrm{d\: =\:Distance\:between\:two\:layers\:of\:the\:crystals}\\\\\mathrm{\theta\: =\: Angle\:of\:incident\:light}

 

As for a given set of lattice planes the value of 'd' is fixed so the possibility of getting maximum reflection depends only on θ. If we increase θ gradually a number of positions will be observed at which there will be maximum reflection.

 

Now,

n\lambda=2d\sin\theta

n=1,\lambda=2.29\AA ,\theta=27^{\circ}8'

So,

d=0.5\times1\times10^{-8}/\sin(\theta=27^{\circ}8')=2.51\AA

 

Posted by

Sumit Saini

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

17 left in NEET toppers list 2024 as physics question strips 44 of top ranks
anam-khan

NEET Revised Result 2024: Joy and disappointment as all-India ranks change by thousands of places
anam-khan

NEET UG 2024 cut-offs drop for all categories; final scorecard out at neet.ntaonline.in

Latest Question