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The diode used in the circuit shown in the figure has a constant voltage drop of \mathrm{0.5\ V} at all currents and a maximumpower rating of \mathrm{100\ milli-watt} . What should be the value of the resistance \mathrm{R}, connected in series with the diode, for obtaining maximum current?

Option: 1

1.5\ \Omega


Option: 2

5\ \Omega


Option: 3

6.67\ \Omega


Option: 4

200\ \Omega


Answers (1)

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\mathrm{\begin{aligned} &\mathrm{ R=\frac{\text { Voltage drop }}{\text { Current }}} \\ &\mathrm{ \therefore \text { Current in circuit, } I=\frac{P}{V}=\frac{100 \times 10^{-3}}{0.5}=0.2 \mathrm{~A}} \\ &\mathrm{ R=\frac{1}{0.2}=5 \Omega} \end{aligned}}

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Divya Prakash Singh

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