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The displacement of a particle is given by the equation:

s=3t^3+7t^2+5t+8 where s means the meters and t means the seconds. Then, the acceleration of the particle at t=1 is:

Option: 1

14\ \frac{m}{s^2}


Option: 2

18\ \frac{m}{s^2}


Option: 3

32\ \frac{m}{s^2}


Option: 4

None of the above


Answers (1)

best_answer

s=3t^3+7t^2+5t+8

Or, v=\frac{ds}{dt}

Or, 9t^2+14t+5

Or, a=\frac{dv}{dt}=\ 18t+14

Now, At     t=1  

a=32\ \frac{m}{s^2}

Posted by

chirag

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