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  • The electric potential at the surface of an atomic nucleus (z = 50) of radius 9.0 * 10-13 cm is:Option: 1 9 * 105 vol

The electric potential at the surface of an atomic nucleus (z = 50) of radius 9.0 * 10-13 cm is:

Option: 1

9 * 105 volt


Option: 2

8 * 106 volt


Option: 3

80 volt


Option: 4

9 volt


Answers (1)

best_answer

z = number of protons = 50

Charge on one proton = +e = + 1.6 * 10-19C

Charge, q = ze

                = 50 * 1.6 * 10-19C

                = 80 * 10-19C

Now, electric potential:

                v = \frac{kq}{r} = \frac{kze}{r}

                v = \frac{9 * 10^{9} * 80 * 10^{-19}}{9*10^{-15}}

                     = 80 * 10^5 = 8 * 10^6 volt

Posted by

SANGALDEEP SINGH

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