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  • The half life of a radioactive sample undergoing . If

The half life of a radioactive sample undergoing \alpha -decay\: is\: 1.4 \times 10^{17}s. If the number of nuclei in the sample is 2.0\times10 ^{21}, the activity of the sample is nearly

 

Option: 1

10^5\; Bq


Option: 2

10^6\; Bq


Option: 3

10^3 \; Bq


Option: 4

10^4 \; Bq


Answers (1)

best_answer

T_{\frac{1}{2}}= 1.4 \times 10^7 s

Activity = \lambda N

            = \left ( \frac{ln (2)}{t_{\frac{1}{2}}} \right )\times N

            =\frac{0.693}{1.41 \times 10^{17}}\times 2 \times 10^{21}

            = 10^4 dps = 10^4 Bq

[1 disinteration per second = 1Bq]

Posted by

shivangi.bhatnagar

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