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  • The half-life period of a first-order reaction is 1386 seconds. The specific rate constant of the reaction is:Option: 1 0.5 x 10-2 s-

The half-life period of a first-order reaction is 1386 seconds. The specific rate constant of the reaction is:

Option: 1

0.5 x 10-2 s-1


Option: 2

0.5 x 10-3 s-1


Option: 3

5.0 x 10-2 s-1


Option: 4

5.0 x 10-3 s-1


Answers (1)

best_answer

For the first-order reactions,

Unit of k=sec^{-1}

t_\frac{1}{2}=\frac{0.693}{k}

Hence,

k=\frac{0.693}{1386}=5\times 10^{-4}s^{-1}=0.5 \times 10^{-3}s^{-1}

The Correct answer is option 2.

Posted by

Irshad Anwar

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