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The initiation of transcription is a complex process involving promoter recognition, conversion of the initial closed to open form, abortive initiation events, and finally promoter escape. The following statements are the steps in transcription initiation:
A. Promoter escape in bacteria is usually accompanied by the release of the sigma factor from the RNA p holoenzyme complex.
B. Abortive initiation events in prokaryotes result in the formation of short transcripts ~10 nucleotides events in eukaryotes result in formation of transcripts ~75 nucleotides in length.
C. Promoter escape in eukaryotes is accompanied by the phosphorylation of the RNA polymerase large terminal domain (CTD).
D. Promoter recognition in bacteria is governed by the sigma factor which binds to the -10 and -35 region followed by recruitment of the RNA Pol II core enzyme to form the holoenzyme.
Which one of the following options represents the combination of all correct statements?
A and C only.
B and D only.
A, C and D.
A and D only.
Answers (1)
During transcription initiation in vitro, prokaryotic and eukaryotic RNA polymerase (RNAP) can engage in abortive initiation-the synthesis and release of short (2 to 15 nucleotides) RNA transcripts-before productive initiation. Hence, the correct answer is option 3.
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