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  • The kinetic energy of a free electron is increased by 50%. Then the ratio of initial to final de Broglie wavelength is?  

The kinetic energy of a free electron is increased by 50%. Then the ratio of initial to final de Broglie wavelength is?

 

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Concept- The de Broglie wavelength (λ) of a particle is inversely proportional to the square root of its kinetic energy. $$ 
λ∝ \frac{1}{\sqrt{K}}
$$ 

  • Let the initial kinetic energy = K
  • Final kinetic energy = 50% more than initial = 1.5K

Ratio of initial to final de Broglie wavelength = $$
 \sqrt{\frac{1.5K}{K}}≈ 1.225
$$ 

Posted by

Saniya Khatri

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