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  • The magnetic field B due to a current carrying circular loop of radius 120 cm at its centre is <img alt="5 * 10^{-4} T" src="https://entrancecorner.oncodecogs.com/gif.latex?5%20*%2010%5E%7B-4%

The magnetic field B due to a current carrying circular loop of radius 120 cm at its centre is 5 * 10^{-4} T. Find the B-field due to the loop at a point on the axis at a distance of 50 cm from the centre.

Option: 1

4 * 10-6 T


Option: 2

5 * 10-6 T


Option: 3

6 * 10-6 T


Option: 4

3 * 10-6 T


Answers (1)

best_answer

By symmetry each of the wire AB and BC carries a current of 5A.

\frac{d F}{d t}=\frac{\mu_0 i_1 i_2}{2 \pi d}

=\frac{\left(2 \times 10^{-7} \mathrm{TmA}^{-1}\right)(5 \mathrm{~A})(5 \mathrm{~A})}{\left(1 \times 10^{-2} \mathrm{~m}\right)}

\begin{aligned} & =\frac{50 \times 10^{-7}}{10^{-2}} \mathrm{~N} / \mathrm{m} \\ & =5 \times 10^{-4} \mathrm{~N} / \mathrm{m} \end{aligned}

Posted by

manish painkra

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