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The magnetic force acting on a charged particle of charge - 2ue in a magnetic field of 2T acting in y direction, when the particle velocity is

(2 \bar{i}+3 \bar{j}) \times 10^6 \mathrm{~ms}^{-1} \text {, is }

Option: 1

4N in z direction


Option: 2

8N in y direction


Option: 3

8N in z direction


Option: 4

8N in -z direction


Answers (1)

best_answer

The magnetic force acting on the charged particle is given by

\begin{aligned} & \vec{F}=q(\bar{v} \times \vec{B}) \\ = & \left.\left(-2 \times 10^{-6}\right)\left[\{2 \vec{i}+3 \bar{j}) \times 10^6\right\} \times(2 \bar{j})\right] \\ = & -4(2 \bar{k}) \\ = & -8 \dot{k} \end{aligned}

\therefore Force is of 8N along negative z - axis

Posted by

shivangi.shekhar

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