The ratio of contributions made by the electric field and magnetic field components to the intensity of the electromagnetic wave is: (c = speed of electromagnetic wave)
Option: 1  c : 1
Option: 2  1 : 1
Option: 3 1 : c  
Option: 4  1 : c2

Answers (1)

Intensity of EM wave is

I=u_{av}C

For electric field 

(u_{\mathrm{av}})_E=\frac{1}{4} \varepsilon_{0} E_{0}^{2}

and for magnetic field (u_{\mathrm{av}})_B= \frac{1}{4 \mu_{0}} B_{0}^{2}

\text {Now, as we know, } \quad E_{0}=c B_{0} \text { and } \mu_{0} \varepsilon_{0}=\frac{1}{c^{2}} \text { so that, } \mu_{0}=\frac{1}{\varepsilon_{0} c^{2}} \text { and, }

So \frac{1}{4 \mu_{0}} B_{0}^{2}=\frac{\varepsilon_{0} c^{2}}{4}\left(\frac{E_{0}}{c}\right)^{2}=\frac{1}{4} \varepsilon_{0} E_{0}^{2}

So \frac{I_E}{I_B}=1

 

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