Get Answers to all your Questions

header-bg qa

The transition metal ion M^{2+} forms a green-coloured compound when combined with a ligand. If 0.025 moles of M^{2+} ions react with excess ligand, what mass of the green-coloured compound will be formed? (The compound's molar mass is 300 g/mol)

Option: 1

7.5 g


Option: 2

 0.75 g


Option: 3

75 g


Option: 4

0.075 g


Answers (1)

best_answer

To determine the mass of the green-coloured compound formed, we need to use the concept of moles and molar mass. First, we calculate the number of moles of M^{2+}ions:

Number of moles = given mass divided by the molar mass
Number of moles = 0.025\, moles
Since the M^{2+} ions react with excess ligand, all the moles of M^{2+} ions will form the green-coloured compound. Therefore, the number of moles of the green-coloured compound is also 0.025 moles.
 

Now, we can calculate the mass of the compound using the equation:

Mass is calculated as moles multiplied by molar mass.
Mass= 0.025 \ moles\: \times \: 300\ g/mol
Mass= 7.5 g

Hence, the mass of the green-coloured compound formed is 7.5 grams. Therefore, the correct answer is option 1) 7.5 g.

Posted by

Riya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks