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  • The wave front of a light beam is given by the equation . The ang

The wave front of a light beam is given by the equation x+2y+3z=constant. The angle made by the direction of light with the y-axis is

Option: 1

\cos ^{-1}\left ( \frac{1}{\sqrt{14}} \right )


Option: 2

\sin ^{-1}\left ( \frac{2}{\sqrt{14}} \right )


Option: 3

\cos ^{-1}\left ( \frac{2}{\sqrt{14}} \right )

 


Option: 4

\sin ^{-1}\left ( \frac{3}{\sqrt{14}} \right )


Answers (1)

best_answer

Answer (3)

Here direction of light is given by vector

\vec{\eta }=i+2j+3k

Hence angle made by \vec{\eta } with y-axis is

\cos \theta=\left ( \frac{2}{\sqrt{14}} \right )\Rightarrow \theta=\cos ^{-1}\left ( \frac{2}{\sqrt{14}} \right )

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Gunjita

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