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The x position of a particle on the x-axis with respect to time t is given by   

x=9t^3-t^2 where x is in meters and t is in seconds.The value of acceleration (in m/s2) at t=1 sec is 

Option: 1

12 


Option: 2

52


Option: 3

30


Option: 4

50


Answers (1)

best_answer

 \\ x=9t^3-t^2 \\ v=\frac{dx}{dt}=27t^2-2t \\ a=\frac{dv}{dt}=54t-2

at t=1 sec

a=52 m/s2

Posted by

Divya Prakash Singh

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