1551350223028948959846.jpg Grey seed colour(G) in pca is (lorninant to V/hitc seed colour(g). In thc following tbc indicated parent with known phenotypes but unknown genotype, produced thc progcny Ji%tcd: FcrnaJc parent Parent Progeny Female x male Gray while (i) Gray x white 81 (ii) Gray x gray 118 (iii) Gray white 74 (iv) Gray x gray 90 Based on the segregation data, the possiblc genotype of each female parent - (J) A-Gg; B-Gg; c-GG; d-GG or Gg (2) A-GG; B-GG; c-GG; d-Gg (3) A-Gg; B-Gg; c-Gg; d-Gg (4) A-gg•, B-gg; c-gg; d-Gg

Answers (3)

@Preethi

Q. 108 the correct option is 1). because C and D haven't produced any white seeds  which means they woun't have any genotype of  white coloured seeds.

@Preethi

Q. 108 ...because in 2) D is having a genotype of both dominat gray and the recessive white. so in their next generation obviously they will produce white progeny, but in the given data D is not having a single white progeny. So the correct option is 1).

Ma'am why can't it be 2

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