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  • Try this! - Chemical Bonding and molecular structure - NEET

Which of the two ions from the list given below that have the geometry that is explained by the same hybridization of orbitals, NO^{-}_{2}, NO^{-}_{3},NH^{-}_{2},NH^{+}_{4}, SCN^{-} ?

  • Option 1)

    NO^{-}_{2}  and NO^{-}_{3}

  • Option 2)

    NO^{+}_{4}  and NO^{-}_{3}

  • Option 3)

    SCN^{-} and NH^{-}_{2}

  • Option 4)

    NO^{-}_{2} and NH^{-}_{2}

 

Answers (1)

best_answer

As we learnt in 

VSEPR Theory -

1.  The shape of the molecule is determined by repulsions between all of the electron pair present in valence shell.

2.  Order of repulsion 

             lone \:pair-Lone\: pair> Lone\:pair-Bond\:pair> Bond\:pair-bond\:pair

3  Repulsion among the bond pair is directly proportional to the bond  order and electronegativity difference between the central atom and the other atom.

-

 

 NO_{2}^{-} hybridization, H=\frac{1}{2}[5+0-0+1]=3,\ sp^{3}\ hybridization

NO_{3}^{-} hybridization, H=\frac{1}{2}[5+0-0+1]=3,\ sp^{2}\ hybridization

\therefore NO_{2}^{-} and NO_{3}^{-} have some hybridization and structure.


Option 1)

NO^{-}_{2}  and NO^{-}_{3}

This is correct option

Option 2)

NO^{+}_{4}  and NO^{-}_{3}

THis is incorrect option

Option 3)

SCN^{-} and NH^{-}_{2}

THis is incorrect option

Option 4)

NO^{-}_{2} and NH^{-}_{2}

THis is incorrect option

Posted by

prateek

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