# If n=6, the correct sequence for filling of electrons will be: Option 1) $ns \rightarrow (n-2)f\rightarrow (n-1)d \rightarrow np$ Option 2) $ns \rightarrow (n-1)d\rightarrow (n-2)f \rightarrow np$ Option 3) $ns \rightarrow (n-2)f\rightarrow np \rightarrow (n-1)d$ Option 4) $ns \rightarrow np (n-1)d \rightarrow (n-2)f$

V Vakul

As we learnt in

Aufbau Principle -

In the ground state of the atoms, the orbitals are filled in order of their increasing energies.

- wherein

In the ground state of atoms, the orbitals are filled in order of their increasing energies.

Clearly for n=6, we have the order 6s, 4f, 5d, 6p or ns, (n-2)f, (n-1)d, np

Option 1)

$ns \rightarrow (n-2)f\rightarrow (n-1)d \rightarrow np$

This solution is correct

Option 2)

$ns \rightarrow (n-1)d\rightarrow (n-2)f \rightarrow np$

This solution is incorrect

Option 3)

$ns \rightarrow (n-2)f\rightarrow np \rightarrow (n-1)d$

This solution is incorrect

Option 4)

$ns \rightarrow np (n-1)d \rightarrow (n-2)f$

This solution is incorrect

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