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Which of the following ions will exhibit colour in aqueous solutions?

  • Option 1)

    Ti^{3+}

  • Option 2)

    La^{3+}

  • Option 3)

    Lu^{3+}

  • Option 4)

    Sc^{3+}

 

Answers (1)

best_answer

As we learnt in

 

Color of 'd' block elements complexes -

Generally, d1- d9  electronic configurated metal complex show color according to the 

E=hv

\because \:\:v=\frac{c}{\lambda }, \; E= \frac{hc}{\lambda }

 

-

 

 

For colour, a metal must have unpaired electrons

Electronic config. of given species:

La^{3+}(Z=57)=[Xe]4f^{0}5d^{0}6s^{0}

Ti^{3+}(Z=22)=[Ar]3d^{1}4s^{0}, in unpaired e^{-}

Lu^{3+}(Z=71)=[Xe] 4f^{14}5d^{0}6s^{0}

Sc^{3+}(Z=21)=[Ar] 3d^{0}4s^{0}

Since, Ti^{3+}is the only species with an unpaired e^{-}, it will display colour in aqueous sol. 


Option 1)

Ti^{3+}

Correct

Option 2)

La^{3+}

Incorrect

Option 3)

Lu^{3+}

Incorrect

Option 4)

Sc^{3+}

Incorrect

Posted by

prateek

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