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Twenty seven drops of same size are charged at 220 V each.They combine to form a bigger drop.calculate the potential of the bigger drop.

Option: 1

660V


Option: 2

1320V


Option: 3

1520V


Option: 4

1980V


Answers (1)

best_answer

V=\frac{kg}{r}=220v  

27\times \frac{4}{3}\pi r^{3}=\frac{4}{3}\pi R^{3}

R=3r

Q Total 27q(by Change convervation)

V_{Bigger\: drop}=\frac{kQ_{total}}{R}=\frac{27kq}{3r}

                                          =q\left ( 220 \right )

V_{Bigger\: drop}=1980v                   

 

Posted by

Ritika Kankaria

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