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Two batteries of different emf and internal resistance are connected as shown. The voltage across OP in volts-

Option: 1

10V


Option: 2

8V


Option: 3

12V


Option: 4

11V


Answers (1)

best_answer

By applying Kirchoff's loop law.

Let I be the current 

\begin{aligned} & 2 I+12-6+4 I=0 \\ & 6 I=-12+6=6 \\ & I=\frac{6}{6}=1 A . \end{aligned}

It means the direction of the current is the same as that we assume.

Hence, I=1A

$$ \begin{aligned} & V_{0}-12+1 \times 2=V_{p} \\ & V_{0}-V_{p}=12-2=10 \mathrm{~V} \\ & V_{0 p}=10 \mathrm{~V} \end{aligned}

 

Posted by

Nehul

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