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What is the oxidation state of xenon in xenon tetrafluoride?

Option: 1


Option: 2


Option: 3



Option: 4


Answers (1)


 The oxidation state of xenon in xenon tetrafluoride \mathrm{(XeF_{4})} is B. +6. It can expand its valence shell by using its d orbitals. In xenon tetrafluoride, each fluorine atom shares one electron with xenon, resulting in four covalent bonds. Since each bond involves the sharing of one electron, the oxidation state of xenon in  xenon tetrafluoride is +6, which is the difference between the number of valence electrons of xenon and the number of electrons shared in the covalent bonds.

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Pankaj Sanodiya

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