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When combustion of ethylene ( $C_{2}H_{4}$ ) takes place it releases carbon dioxide and water. If enthalpy of formation of $C_{2}H_{4}$ is $w$ , for $O_{2}$ is $x$ , for $CO_{2}$ is $y$ and for $H_{2}O$ is $z$ . Then find the enthalpy of reaction:
Option: 1
$y+z-w-x$

Option: 2
$W+3x-2y-2z$

Option: 3
$2y+2z-w-3x$

Option: 4
All of the above

Answers (1)

best_answer

Enthalpy of reaction, $\Delta H=H_{P}-H_{R}$

First write the balanced equation of the reaction

$C_{2}H_{4}+3O_{2}\rightarrow 2CO_{2}+2H_{2}O$

Given

$\Delta H_{f}^{0}C_{2}H_{4}=w$

$\Delta H_{f}^{0}O_{2}=x$

$\Delta H_{f}^{0}CO_{2}=y$

$\Delta H_{f}^{0}H_{2}O=z$

Now, $\Delta H=(2y+2z) - (w+3x) = 2y+2z-w-3x$

Hence, Option number (3) is correct

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