When decahydrate of washing soda is treated with dry air , the product formed in the given process is :
NaHCO3.7H2O
NaHCO3.8H2O
NaHCO3.2H2O
NaHCO3.H2O
As we learnt ,
Na2CO3 crystallises from water as decahydrate. Upon exposure to dry air, it forms monohydrate
Therefore, option (4) is correct.