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When glycerol is treated with excess of HI, it produces

Option: 1

2-iodopropane


Option: 2

Allyl iodide


Option: 3

Propene


Option: 4

Glycerol triiodide


Answers (1)

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When glycerol is treated with an excess of HI, it produces 2-iodopropane.

In the first step, a molecule of glycerol reacts with 3 HI molecules to form an unstable 1,2,3-triiodopropane. This loses a molecule of iodine to form allyl iodide.
Allyl iodide adds a molecule of HI to obtain an unstable molecule which loses a molecule of iodine to form propene.

A molecule of HI is added to propene to form 2-iodopropane. 

                                       

                      

Posted by

Sanket Gandhi

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