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  • When sodium hydroxide reacts with ZnSO4 it forms X, this X is soluble in NaOH excess, due to formation of :Option: 1 Zn(OH)2</p

When sodium hydroxide reacts with ZnSO4 it forms X, this X is soluble in NaOH excess, due to formation of :

Option: 1

Zn(OH)2


Option: 2

ZnO


Option: 3

Na2ZnO2


Option: 4

All of these


Answers (1)

best_answer

As we learnt ,

 

 

Reaction of NaOH with salts -

Forming insoluble hydroxides which dissolves in excess of NaOH. Eg. Zn, Al, Sb, Pb, Sn, As

- wherein

ZnSO_{4}+2NaOH\rightarrow Zn(OH)_{2}\downarrow+Na_{2}SO_{4} \\Zn(OH)_{2}+2NaOH\rightarrow Na_{2}ZnO_{2}(sodium\ zincate)+2H_{2}O

 

 Zn(OH)_{2}+2NaOH\rightarrow Na_{2}ZnO_{2}(sodium\ zincate)

Sodium zincate is soluble in NaOH .

Therefore, option(3) is correct.

 

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