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When sodium hypobromide reacts with weakly electropositive metal to liberate :

Option: 1

H2 gas


Option: 2

O2 gas


Option: 3

H2O vapours


Option: 4

All of these


Answers (1)

best_answer

As we learnt ,

 

Reaction of NaOH with metals -

Weakly electro-positive metals dissolve in NaOH solution to liberate hydrogen

- wherein

M+2NaOH\rightarrow Na_{2}MO_{2}+H_{2}

Where M=Zn, Al, Sn

 

 M+2NaOH\rightarrow Na_{2}MO_{2}+H_{2} \uparrow

M \rightarrow weak electropositive metal

Therefore, option (1) is correct.

 

 

Posted by

Deependra Verma

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