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When X-rays of wavelength \mathrm{0.5 \AA} would be transmitted by an aluminium tube of thickness \mathrm{7 \mathrm{~mm}}, its intensity remains one-fourth. The attenuation coefficient of aluminium for these \mathrm{X}-rays is
 

Option: 1

0.188 \mathrm{~mm}^{-1}

 


Option: 2

0.189 \mathrm{~mm}^{-1}
 


Option: 3

0.198 \mathrm{~mm}^{-1}
 


Option: 4

None of these


Answers (1)

best_answer

\mathrm{ \frac{\mathrm{I}_0}{\mathrm{I}}=4, \quad \mathrm{x}=7 \mathrm{~mm} \text { (given) } }

\mathrm{ \Rightarrow \mu=\frac{2.303 \log _{10} \frac{\mathrm{I}_0}{\mathrm{I}}}{\mathrm{x}} }

\mathrm{ \mu=\frac{2.303 \log _{10} 4}{7}=\frac{2.303 \times 0.6023}{7}}

\mathrm{ \mu=0.198 \mathrm{~mm}^{-1}}

Hence option 3 is correct.



 

Posted by

Ritika Kankaria

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