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Which of the following easily reacts with water producing hydrogen ?

Option: 1

\mathrm{PH}_3


Option: 2

\mathrm{CH}_4


Option: 3

\mathrm{B}_2 \mathrm{H}_6


Option: 4

\mathrm{H}_2 \mathrm{S}


Answers (1)

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\mathrm{PH}_3 is non-polar compound and thus, it doesn't dissolve in water. There is no reaction between them.

\mathrm{CH}_4  does not react with water but it reacts with steam to form carbon dioxide, carbon monoxide and hydrogen. This reaction is endothermic so it needs external heat for the reaction to take place.

\mathrm{H}_2 \mathrm{S} does not react with water, it just dissociate into \mathrm{HS}^{-}, \mathrm{S}^{2-} and \mathrm{H}^{+} in water. \mathrm{B}_2 \mathrm{H}_6 reacts violently with water to form hydrogen and boric acid.

\mathrm{B}_2 \mathrm{H}_6+6 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{~B}(\mathrm{OH})_3+6 \mathrm{H}_2 \uparrow ; \Delta \mathrm{H}=-466 \mathrm{~kJ} / \mathrm{mol}

Enthalpy of reaction is negative which means it is exothermic reaction.

Hence, Diborane react easily with water to produce hydrogen.

Posted by

mansi

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