Q.59) Which one of the following reactions does, NOT give benzene as the product?
A)
B)
C)
D) $\mathrm{H}-\mathrm{C}=\mathrm{C}-\mathrm{H} \xrightarrow[\text { at } 873 \mathrm{~K}]{\text { red hot lron Tube }}$
1) BDC react with warm water Gives Phenol as product via loss of N? gas and replacement by H
2)$\mathrm{C}_6 \mathrm{H}_5 \mathrm{COONa}+\mathrm{NaOH} \xrightarrow{\Delta} \mathrm{C}_6 \mathrm{H}_6+\mathrm{Na}_2 \mathrm{CO}_3$
3) n -Hexane $+\mathrm{Mo}_2 \mathrm{O}_3$ at $773 \mathrm{~K}, 10-20 \mathrm{~atm}$
$\rightarrow$ This is aromatization, where $n$-hexane gets converted to benzene under high temperature and pressure with catalyst.
4) $3 \mathrm{HC} \equiv \mathrm{CH} \xrightarrow{873 \mathrm{~K}, \mathrm{Fe}} \mathrm{C}_6 \mathrm{H}_6$
So the correct option is (1)