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Which one of the following will yield alcohol upon treatment with aq. KOH ?

Option: 1


Option: 2

CH3CH2-Cl


Option: 3


Option: 4


Answers (1)

best_answer

As we learnt ,

 

Preparation of alcohol -

By treatment with  ag.KOH  or moist  Ag2O

- wherein

RX+KOH(ag)\rightarrow ROH+KX


RX+Ag_{2}O(moist)\rightarrow ROH+AgX

 

 Primary haloalkanes upon treatment with aq. KOH yields alcohols. Tertiary halides, with strong base prefer to undergo E2 elimination reaction.

CH_{3}CH_{2}Cl + aq. KOH \rightarrow CH_{3}CH_{2}OH

Therefore, option (2) is correct.

 

Posted by

Rishabh

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