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Medical
4 days, 18 hours ago

In which case change in entropy is negative?

  • Option 1)

    Evapouration of water

  • Option 2)

    Expansion of a gas at constant temperature

  • Option 3)

    Sublimation of solid to gas

  • Option 4)

    2H_{(g)} \rightarrow H_2_{(g)}

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P Plabita
Answered 3 days, 18 hours ago
  Gibb's free energy (? G) -   - wherein Gibb's free energy enthalpy of reaction entropy temperature       degree of randomness decreases  entropy decreases and is negative.Option 1)Evapouration of waterOption 2)Expansion of a gas at constant temperatureOption 3)Sublimation of solid to gasOption 4)
Medical
1 week, 4 days ago

Match the following:

(a) Pure Nitrogen                (i) Chlorine

(b) Haber process              (ii) Sulphuric Acid

(c) Contact process           (iii) Ammonia

(d) Deacon's process        (iv) Sodium azide or Barium Azide

Which of the following is the correct option?

(a)    (b)    (c)    (d)

  • Option 1)

    (i)    (ii)    (iii)    (iv)

  • Option 2)

    (ii)    (iv)    (i)    (iii)

  • Option 3)

    (iii)    (iv)    (ii)    (i)

  • Option 4)

    (iv)    (iii)    (ii)    (i)

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V Vakul Arora
Answered 1 week, 3 days ago
Option 4 a) Pure Nitrogen  Sodium azide  or Barium azide  b) Haber process  Making ammonia                                        c) Contact process  producing sulphuric acid  d) Deacon's process  Pruduces  gas                                              Option 1)(i)    (ii)    (iii)    (iv)Option 2)(ii)    (iv)    (i)    (iii)Option 3)(iii)    (iv)    (ii)    (i)Option 4)(iv)    (iii)    (ii)    (i)
Medical
1 week, 4 days ago

The mixture that forms maximum boiling azeotrope is:

  • Option 1)

    Water + Nitric Acid

  • Option 2)

    Ethanol + Water

  • Option 3)

    Acetone + Carbon disulphide

  • Option 4)

    Heptane + Octane

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P Plabita
Answered 1 week, 3 days ago
The Solutions that show large negative deviation from Raoult's law from maximum boiling azeotrope at a specific combination. Nitric acid and water is the example of this class of azeotrope.  68% Nitric acid + 32% by mass with a boiling point of 393.5 K.    Option 1)Water + Nitric AcidOption 2)Ethanol + WaterOption 3)Acetone + Carbon disulphideOption 4)Heptane + Octane
Medical
1 week, 4 days ago

Among the following, the one that is not a greenhouse gas is:

  • Option 1)

    nitrous oxide

  • Option 2)

    methane

  • Option 3)

    ozone

  • Option 4)

    sulphur dioxide

 

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S solutionqc
Answered 1 week, 3 days ago
N2O (Nitrous oxide) CH4 (Methane) O3 (Ozone) All the above are greenhouse gases but SO2  is not greenhouse gas.  Option 1) nitrous oxide Option 2) methane Option 3) ozone Option 4) sulphur dioxide
Medical
1 week, 4 days ago

The correct structure of tribromooctaoxide is:

 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

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K Kallem Alekya
Answered 1 week, 3 days ago

option 1 ,because it is not an ion

Medical
1 week, 4 days ago

The number of sigma (\sigma) and pi(\pi) bonds in pent-2-en-4-yne is:

  • Option 1)

    10 \sigma bonds and 3 \pi bonds

  • Option 2)

    \sigma bonds and 5 \pi bonds

  • Option 3)

    11 \sigma bonds and 2 \pi bonds

  • Option 4)

    13 \sigma bonds and no \pi bonds

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V Vakul Arora
Answered 1 week, 3 days ago
Option 1 Structure of pent-2-en-4-yne Here there are 10  bonds  and  bonds And 3  bonds   and Option 1)10  bonds and 3  bondsOption 2)8  bonds and 5  bondsOption 3)11  bonds and 2  bondsOption 4)13  bonds and no  bonds
Medical
1 week, 4 days ago

An alkane "A" on reaction with O3 and Zn-H2O gives propane and ethanal in equimolar ratio. Addition of HCl to Alkane "A" gives "B" as the major product. The structure of the product "B" is

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

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S solutionqc
Answered 1 week, 3 days ago
This oxidation of alkene occurs at the double bond. Thus, propane & ethanol must combine to give the alkene             (Propanone)                                                                                                       Now this reacts with HCl to form B as follows:                                                                         ...
Medical
1 week, 4 days ago

Match the Xenon compound in Column-I with its structure in Column-II and assign the correct code:

Column-I                        Column-II

(a) XeF4                            (i) pyramidal

(b) XeF6                            (ii) Square planar

(c) XeOF4                        (iii) distorted octahedral

(d) XeO3                          (iv) square pyramidal

Code:

            (a)     (b)     (c)     (d)

 

  • Option 1)

    (i)     (ii)     (iii)     (iv)

  • Option 2)

    (ii)      (iii)     (iv)     (i)

  • Option 3)

    (ii)     (iii)     (i)     (iv)

  • Option 4)

    (iii)     (iv)     (i)     (ii)

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S solutionqc
Answered 1 week, 3 days ago
XeF4  it is square planar. XeF6  it is distorted octahedral because of the lone pair present. XeOF4  Its is square pyramidal & its hybridization is sp3d2 XeO3  Its hybridization is sp3 & its shape is pyramidal.  (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i) Option 2 is correct.Option 1)(i)     (ii)     (iii)     (iv)Option 2)(ii)      (iii)     (iv)     (i)Option 3)(ii)     (iii)     (i)   ...
Medical
1 week, 4 days ago

Which mixture of the solution will lead to the formation of negatively charged colloidal [AgI]I^- sol. ?

  • Option 1)

    50 mL of 1 M AgNO_3 + 50 mL of 1.5 M KI

  • Option 2)

    50 mL of 1 M AgNO_3 + 50 mL of 2 M KI

  • Option 3)

    50 mL of 2 M AgNO_3 + 50 mL of 1.5 M KI

  • Option 4)

    50 mL of 0.1 M AgNO_3 + 50 mL of 0.1 M KI

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P Plabita
Answered 1 week, 3 days ago
Option 2                     Negatively charged colloidal  need 2 mol of   Option 1)50 mL of 1 M  + 50 mL of 1.5 M Option 2)50 mL of 1 M  + 50 mL of 2 M Option 3)50 mL of 2 M  + 50 mL of 1.5 M Option 4)50 mL of 0.1 M  + 50 mL of 0.1 M 
Medical
1 week, 4 days ago

Which of the following is incorrect statement?

  • Option 1)

    PbF4 is covalent in nature

  • Option 2)

    SiCl4 is easily hydrolysed

  • Option 3)

    GeX4 (X = F, Cl, Br, I) is more stable than GeX2

  • Option 4)

    SnF4 is ionic in nature

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S solutionqc
Answered 1 week, 3 days ago
(i) PbF4 is not covalent in nature. Because Pb atom is very & F atom is very small, so according to Fajan's rule, PbF4 is not covalent. (ii) SiCl4 is not a very stable compound because of steric hindrance thus can be hydrolysed very easily (iii) GeX4 is more stable than GeX2 as in GeX4 all the orbitals are fully filled.  (iv) SnF4 is ionic in nature. Because F atom is very small & Sn atom is...
Medical
1 week, 4 days ago

What is the correct electronic configuration of the central atom in K_6[Fe(CN)_6] based on crystal field theory?

  • Option 1)

    t_{2g}^4e_{g}^2

  • Option 2)

    t_{2g}^6e_{g}^0

  • Option 3)

    e^3t_2^3

  • Option 4)

    e^4t_2^2

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S solutionqc
Answered 1 week, 3 days ago
Splitting occurs as follows for octahedral For Fe2+ (d6), electron distribution occurs as follows:  is the correct distribution. Option 2 is correct.  Option 1)Option 2)Option 3)Option 4)
Medical
1 week, 4 days ago

The non-essential amino acid among the following is:

  • Option 1)

    valine

  • Option 2)

    leucine

  • Option 3)

    alanine

  • Option 4)

    lysine

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S solutionqc
Answered 1 week, 3 days ago
Non essential amino acids are those which produce in the human body itself. Essential amino acids are those which do not produce in the human body & we have to take them from outside sources. Alanine is the non-essential amino acid. Option 3 is correct.Option 1)valineOption 2)leucineOption 3)alanineOption 4)lysine
Medical
1 week, 4 days ago

For an ideal solution, the correct option is:

  • Option 1)

    \Delta_{mix}S = 0 at constant T and P

  • Option 2)

    \Delta_{mix}V \neq 0 at constant T and P

  • Option 3)

     \Delta_{mix}H = 0 at constant T and P

  • Option 4)

    \Delta_{mix}G = 0 at constant T and P

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S solutionqc
Answered 1 week, 3 days ago
For an ideal solution, the Gibbs free energy is always negative, thus their mixing is always spontaneous. The volume change of the mixing of ideal solutions is zero. An ideal solution is one in which the enthalpy of the solution is zero  at constant T and P Option 3 is correct.Option 1) at constant T and POption 2) at constant T and POption 3)  at constant T and POption 4) at constant T and P
Medical
1 week, 4 days ago

For the cell reaction

2Fe^{3+}(aq)+ 2I^{-}(aq) \rightarrow 2Fe^{2+}(aq) + I_2(aq)

E^0_{cell} = 0.24V at 298K. The standard Gibbs energy (\Delta_r G^0) of the cell reaction is:

[Given that Faraday constant F = 96500 C mol-1]

  • Option 1)

    -46.32 kJ mol-1

  • Option 2)

    -23.16 kJ mol-1

  • Option 3)

    46.32 kJ mol-1

  • Option 4)

    23.16 kJ mol-1

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S solutionqc
Answered 1 week, 3 days ago
We know that       Option 1 is correctOption 1)-46.32 kJ mol-1Option 2)-23.16 kJ mol-1Option 3)46.32 kJ mol-1Option 4)23.16 kJ mol-1
Medical
1 week, 4 days ago

Enzymes that utilize ATP in phosphate transfer require an alkaline earth metal (M) as the cofactor M is:

  • Option 1)

    Be

  • Option 2)

    Mg

  • Option 3)

    Ca

  • Option 4)

    Sr

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P Plabita
Answered 1 week, 3 days ago
Option 2 Mg is the alkaline earth metal as the co-factor. (FACT)Option 1)BeOption 2)MgOption 3)CaOption 4)Sr
Medical
1 week, 4 days ago

A compound is formed by cation C and anion A. The Anions form hexagonal close packed lattice and the cations occupy 75% of the octahedral void. The formula of the compound is

  • Option 1)

    C_2A_3

  • Option 2)

    C_3A_2

  • Option 3)

    C_3A_4

  • Option 4)

    C_4A_3

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S solutionqc
Answered 1 week, 3 days ago
Option 3 Anions: No of ions per unit in HCP = 6 Cations: No of octahedral voids in HCP = 6                         So, 75% of 6 = 4.5     Option 1)Option 2)Option 3)Option 4)
Medical
1 week, 4 days ago

A gas at 350K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The  correct  option about the gas and its compressibility factor (Z) is:

  • Option 1)

    Z>1 and attractive forces are dominant

  • Option 2)

    Z>1 and repulsive forces are dominant

  • Option 3)

    Z<1 and attractive forces are dominant

  • Option 4)

    Z<1 and repulsive forces are dominant

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P Plabita
Answered 1 week, 3 days ago
Option 3          Molar volume of gas is 20% smaller than that of the ideal gas. Hence Z < 1 and attractive forces are dominant. When Z < 1: Gas shows negative deviation and is more compressible than expected from ideal behaviour.  Z < 1 corresponds to attractive forces between molecules.Option 1)Z>1 and attractive forces are dominantOption 2)Z>1 and repulsive forces are dominantOption 3)Z<1...
Medical
1 week, 4 days ago

The biodegradable polymer is:

  • Option 1)

    nylon-6,6

  • Option 2)

    nylon 2 - nylon 6

  • Option 3)

    nylon-6

  • Option 4)

    Buna-S

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P prateek
Answered 1 week, 3 days ago
Option 2  Biodegradable polymer is Nylon-2-Nylon-6 monomers: Glycine, aminocaproic acid Option 1)nylon-6,6Option 2)nylon 2 - nylon 6Option 3)nylon-6Option 4)Buna-S
Medical
1 week, 4 days ago

For the chemical reaction

N_2(g) + 3H_2(g)\leftrightharpoons 2NH_3(g)

the correct option is:

 

  • Option 1)

    -\frac{1}{3}\frac{d[H_2]}{dt} = -\frac{1}{2}\frac{d[NH_3]}{dt}

  • Option 2)

    -\frac{d[N_2]}{dt} = {2}\frac{d[NH_3]}{dt}

  • Option 3)

    -\frac{d[N_2]}{dt} = \frac{1}{2}\frac{d[NH_3]}{dt}

  • Option 4)

    {3}\frac{d[H_2]}{dt} ={2}\frac{d[NH_3]}{dt}

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S solutionqc
Answered 1 week, 3 days ago
For a chemical reaction: The rate is always given as:  for the reaction: , Thus,  Option 3 is correct.Option 1)Option 2)Option 3)Option 4)
Medical
1 week, 4 days ago

Under isothermal condition, a gas at 300K expands from 0.1L to 0.25L against a constant external pressure of 2 bar. The work done by the gas is:

[Given that 1L bar = 100 J]

  • Option 1)

    -30 J

  • Option 2)

    5 kJ

  • Option 3)

    25 J

  • Option 4)

    30 J

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S solutionqc
Answered 1 week, 3 days ago
We know that the work done is given as: Now, Option 1 is correct.Option 1)-30 JOption 2)5 kJOption 3)25 JOption 4)30 J
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