i) Solve using appropriate Euclid’s axiom: In Fig. 5.12: AB = BC, M is the mid-point of AB and N is the mid-point of BC. Show that AM = NC.
ii) Solve using appropriate Euclid’s axiom: In Fig. 5.12: BM = BN, M is the mid-point of AB and N is the mid-point of BC. Show that AB = BC.
i) Here AB = BC
If M is the midpoint of AB then
AM = MB = 0.5AB
If N is the midpoint of BC then
BN = NC = 0.5 BC
According to Euclid’s axiom, things which are halves of the same thing are equal.
We have, AB = BC
Multiply both sides by 0.5
0.5 AB = 0.5 BC
AM = NC
Hence proved.
ii) Here, BM = BN
If M is the mid-point of AB then
AM = MB
2AM = 2BM = AB
If N is the mid-point of BC then
BN = NC
2BN = 2NC = BC
According to Euclid’s axiom, things which are double of the same thing are equal to one another.
Now, BM = BN
Multiply both sides by 2
2BM = 2BN
Hence,
AB = BC
Hence proved.