# 2.20    A   solution (by mass) of cane sugar in water has freezing point of    Calculate the freezing point of    glucose in water if freezing point of pure water is

It is given that freezing point of pure water is 273.15 K.

So, elevation of freezing point = 273.15 - 271 = 2.15 K

solution means 5 g solute in 95 g of water.

Moles of cane sugar :

Molality :

We also know that -

or

Now we will use the above procedure for glucose.

of glucose means 5 g of gluocse in 95 g of H2O.

Moles of glucose :

Thus molality :

So,  we can find the elevation in freezing point:

Thus freezing point of glucose solution is 273.15 - 4.09  = 269.06 K.

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