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Q 7.     A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a  friction force of 5000 N, then calculate: 

    (b)     the acceleration of the train

Answers (1)


We know that the force is given by :

                                            F\ =\ ma

or                                 35000\ =\ (8000\ +\ 10000)a

or                                         a\ =\ \frac{35000}{18000}\ =\ 1.944\ m/s^2

Thus acceleration of the train is   1.944\ m/s^2.

Posted by

Sanket Gandhi

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