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The octahedral complex \mathrm{CoSO_{4}Cl\cdot 5NH_{3}} exists in two isomeric forms \mathrm{x} and \mathrm{y} . Isomer \mathrm{x} reacts with \mathrm{AgNO_{3}} to give a while precipitate,but does not react with \mathrm{BaCl_{2}} . Isomer \mathrm{y} gives white precipitate with \mathrm{BaCl_{2}} but does not react with \mathrm{AgNO_{3}}.

Isomers \mathrm{x} and \mathrm{y} are

Option: 1

ionization isomers


Option: 2

linkage isomers


Option: 3

co-ordination isomers


Option: 4

solvate isomers


Ionization isomers have the same central metal ion; only the ligands exchange place with anion or neutral ion outside of the co-ordination complex. The sole difference between the two isomers is which ligands are attached to the central metal.

The X isomer of \mathrm{CoS{{O}_{4}}Cl\cdot 5\text{ N}{{\text{H}}_{3}}} is \mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]Cl}and the Y isomer is \mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]S{{O}_{4}}}

Their reactions are as follows:

\mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]Cl\text{ }\left( X \right)\text{ }\xrightarrow{AgN{{O}_{3}}}AgCl\downarrow \text{ (white ppt}\text{.)}}

\mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]S{{O}_{4}}\text{ (Y) }\xrightarrow{BaC{{l}_{2}}}BaS{{O}_{4}}\downarrow \text{ (white ppt}\text{.)}}

The correct answer is Option A- Ionization isomers.

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Posted by

Gautam harsolia

In a one component second order reaction,if the concentration of the reactant is reduced to half , the rate

Option: 1

increases two times


Option: 2

increases four times


Option: 3

decreases to one half


Option: 4

decreases to one fourth


As we have learnt,

For a second order Reaction

\mathrm{Rate = k [Reactant]^2}

So when the [Reactant] is halved, rate will become one-fourths

Hence, the correct answer is Option (4)

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Posted by

Gautam harsolia

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When cell has stalled DNA replication fork, which checkpoint should be predominantly activated?

Option: 1

G1/S

 

Option: 2

G2/M

 

 

 

Option: 3

M

 

 

Option: 4

Both G2 M and M

 

G2/M should be activated as the cell has stalled DNA replication fork.

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Posted by

Ajit Kumar Dubey

Design an activity to show that chlorophyll is essential for photosynthesis.
 

Explain two neutralisation reaction relaxed to daily life situations

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Posted by

Iniya

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(a) Two lamps rated 100\; W,\; 220\; V and 10\; W,\; 220\; V are connected in parallel to 220\; V supply. Calculate the total current through the circuit. (b) Two resistors X and Y of resistances 2\; \Omega and 3\; \Omega respectively are first joined in parallel and then in series. In each case the voltage supplied is 5\; V. (i) Draw circuit diagrams to show the combination of resistors in each case. (ii) Calculate the voltage across the 3\; \Omega resistor in the series combination of resistors.
 

(a)   I1 = P1/V

I1 = 100 W/ 220 V = 10/  22 A

I2 = P2 / V = 10/ 220 = 1/ 22 A

I = I1 + I2 = = 0.5 A

(b)

(i) Circuit diagrams to show the combination of resistors in each case- 

(ii) Net R=R1+R2=2+3=5 ?

I = V/ Rnet = 5 / 5 = 1A

∴ Voltage across 3? resistor - 

∴ V = 1 × 3 = 3V

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Posted by

Safeer PP

Give reasons : (a) Ventricles have thicker muscular walls than atria. (b) Transport system in plants is slow. (c) Circulation of blood in aquatic vertebrates differs from that in terrestrial vertebrates. (d) During the daytime, water and minerals travel faster through xylem as compared to the night. (e) Veins have valves whereas arteries do not.
 

a) because ventricles have to pump blood out of the heart.

b) because plants are not motile and have a large proportion of dead cells in many tissues and due to which their energy needs are low and have a slow transport system.

c) because the terrestrial vertebrates take oxygen from the air through their lungs and the aquatic invertebrates take oxygen from the water through their gills.

d) because the rate of transpiration is higher during the daytime as compared to night.

e) because arteries don't require valves, as the pressure from the heart is so strong that blood is only able to flow in one direction.

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Posted by

Safeer PP

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In the question two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from the codes (i), (ii), (iii) and (iv) as given below. Assertion (A) : At high temperatures, metal wires have a greater chance of short circuiting. Reason (R) : Both resistance and resistivity of a material vary with temperature.  
Option: 1 Both (A) and (R) are true and (R) is correct explanation of the assertion (A).
Option: 2 Both (A) and (R) are true, but (R) is not the correct explanation of the assertion (A).
Option: 3 (A) is true, but (R) is false.
Option: 4 (A) is false, but (R) is true.

Both (A) and (R) are true, but (R) is not the correct explanation of the assertion (A).

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Safeer PP

In the question two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct
answer to these questions from the codes (i), (ii), (iii) and (iv) as given below. Assertion (A) : Carbon has a strong tendency to either lose or gain electrons to attain noble gas configuration. Reason (R) : Carbon has four electrons in its outermost shell and has the tendency to share electrons with carbon or other                       elements.
Option: 1 Both (A) and (R) are true and (R) is correct explanation of the assertion (A).
Option: 2 Both (A) and (R) are true, but (R) is not the correct explanation of the assertion (A).
Option: 3 (A) is true, but (R) is false.
Option: 4 (A) is false, but (R) is true.

(A) is false, but (R) is true.

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Safeer PP

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An element X is forming acidic oxide. Its most probable position in the modern periodic table is
Option: 1 Group 1 and Period 3
Option: 2 Group 16 and Period 3
Option: 3 Group 17 and Period 3
Option: 4 Group 2 and Period 3

Group 16 and Period 3

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Safeer PP

An element X with atomic number 12 forms a compound with element Y with atomic number 17. The formula of the compound formed is
Option: 1 XY  
Option: 2 XY_{2}
Option: 3 X_{2}Y
Option: 4 X_{2}Y_{3}

The formula of the compound formed is XY_{2}

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Posted by

Safeer PP

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