Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (iii) P(A or B)

17(iii) A and B are events such that  P(A) \small =0.42 , P(B) \small =0.48  and P(A and B) \small =0.16. Determine (iii)  P(A or B) 

Answers (1)

best_answer

Given, P(A) = 0.42,  P(B) = 0.48 and  P(A and B) = 0.16

(iii) We know,

  P(A \cup B) = P(A)+ P(B) - P(A \cap B)

\implies P(A \cup B) = 0.42 + 0.48 - 0.16 = 0.9 - 0.16

 = 0.74

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th Result 2026: Board refutes OSM glitch claims, says Class 12 results likely in third week of May
anam-khan

CBSE 12th Result 2026 LIVE: Class 12 scores soon at cbse.gov.in, how to check, digilocker, pass percentage
anam-khan

CBSE 12th Result 2026 Date LIVE: Class 12 marksheet on cbse.gov.in, DigiLocker soon; OSM system, passing marks

Latest Question