get app

Go To Your Study Dashboard

Filters

CBSE 11 Class

Maths

Probability

Select Exercise

16.3

Q&A - Ask Doubts and Get Answers

Q

A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (i) P(not A)

17.(i) A and B are events such that P(A) $\small =0.42$ , P(B) $\small =0.48$ and P(A and B) . $\small =0.16$ Determine (i) P(not A)

Answers (1)

Views

H Harsh Kankaria

Given, P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16

(i) $P(not\ A) = P(A') = 1 - P(A)$

$\implies$ $P(not\ A) = 1 - 0.42 = 0.58$

Therefore, P(not A) = 0.58

Similar Questions

Related Chapters

Exams

Articles

Questions