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A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.

Q.8.     A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.

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  A bag contains 5 black and 6 red balls.

2 black balls can be selected in ^5C_2  ways and 3 red balls can be selected in ^6C_3 ways.

Thus, using multiplication priciple, number of ways of selecting 2 black and 3 red balls  =^5C_2 .^6C_3

                                                                                                                =\frac{5!}{2!3!}\times \frac{6!}{3!3!}

                                                                                                               =10\times 20=200

                                                                                                              

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