Q2 (a) A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the work done by the applied force in 10 s,
Using Newton's law we can write :
The frictional force is given by :
Its direction will be opposite of the direction of the motion. Thus acceleration produced will be negative.
Thus the net acceleration is = 3.5 - 0.98 = 2.52 m/s2.
The total distance travelled is given by :
Hence the work done by applied force is given by :