# 4.  A card is selected from a pack of $\small 52$ cards.(c) Calculate the probability that the card is (ii) black card.

Number of possible outcomes, n(S) = 52

Let E be the event that the card is a black card. There are 26 black cards. (Diamonds and Clubs)

$\therefore$ n(E) = 26

$\therefore$ $\dpi{100} P(E) = \frac{n(E)}{n(S)}$  $= \frac{26}{52} = \frac{1}{2}$

The required probability that the card is an ace is $\dpi{80} \frac{1}{2}$.

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