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A compound forms hexagonal close-packed structure.

1.15  A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 \; mol of it? How many of these are tetrahedral voids?

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Amount of compound given = 0.5 mol

We know that,                         

                                                 Moles = \frac{No.\ of\ atoms}{6.022 \times 10^{23}}

                                 So, No. of atoms  =0.5\times 6.022 \times 10^{23} = 3.011 \times10^{23} atoms

 

We also know that, No. of tetrahedral voids =   2(No. of atoms in closed packing)

                                                                       =2\times 3.011 \times10^{23} = 6.011\times10^{23}

                                      No. of octahedral voids = No. of atoms present in closed packing.

                                                                             = 3.011 \times10^{23}

So,   Total number of voids =   No. of tetrahedral voids + No. of octahedral voids.

                                           =6.022 \times10^{23} +\ 3.011 \times10^{23}

                                           =9.033 \times10^{23}\ voids 

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