Get Answers to all your Questions

header-bg qa

Q5.6 A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 ms^{-1} to 3.5 ms^{-1} in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

Answers (1)


Since the velocity of the body is increased by applying the force. This is possible only when the force is applied in the direction of the motion.

For finding the magnitude of the force, we need to calculate acceleration.

By using first equation of the motion, 

                                                      v\ =\ u\ +\ at

or                                                  3.5\ =\ 2\ +\ a(25)

or                                                    a\ =\ \frac{3.5-2}{25}\ =\ 0.06\ m/s^2

Thus force can be written as :

                                                 F\ =\ ma

                                                        =\ 3\times 0.06

                                                        =\ 0.18\ N


Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support