Q

A cricketer can throw a ball to a maximum horizontal distance of 100 m .How much high above the ground can the cricketer throw the same ball?

Q. 4.16 A cricketer can throw a ball to a maximum horizontal distance of $100\; m$. How much high above the ground can the cricketer throw the same ball?

Views

We are given the range of projectile motion.

$R\ =\ \frac{u^2\ \sin 2\Theta }{g}$

Substituting values :

$100\ =\ \frac{u^2\ \sin 90^{\circ} }{g}$

So,                                         $\frac{u^2 }{g}\ =\ 100$

Now since deacceleration is also acting on the ball in the downward direction :

$v^2\ -\ u^2\ =\ -2gh$

Since final velocity is 0, so maximum height is given by :

$H\ =\ \frac{u^2}{2g}$

or                                             $H\ =\ 50\ m$

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