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# A die has two faces each with number ‘1’, three faces each with number ‘2’ and one face with number ‘3’. If die is rolled once, determine (iii) P( not 3)

3.(iii) A die has two faces each with number ‘1’, three faces each with number ‘2’ and one face with number ‘3’. If die is rolled once, determine

(iii) P(not 3)

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Total number of faces of a die = 6

(iii) Number of faces with number '3' = 1

$\therefore$ $P(3) = \frac{1}{6}$

$\therefore$ P(not 3) = 1 - P(3)

$= 1-\frac{1}{6} = \frac{5}{6}$

Therefore, required probability P(not 3) is $\frac{5}{6}$

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