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Q A3.      A hammer of mass 500 g, moving at 50 m s-1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?

Answers (1)


Thus the force is given by :

                                                    \\F = m\frac{v-u}{t}\\=500\times10^{-3}(\frac{0-50}{0.01})=-2500N

or                                                        =\ 0.5\times (-5000)\ =\ -2500\ N

The negative sign implies that the force by the nail on the hammer is in the opposite direction.

Posted by

Devendra Khairwa

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