Get Answers to all your Questions

header-bg qa

Q5.13 A man of mass 70 kg stands on a weighing scale in a lift which is moving

(c) upwards with a uniform acceleration of 5 ms^{-2} . What would be the readings on the scale in each case?

Answers (1)


(c) The acceleration of lift is given to be 5 m/s2. Let us assume the upward direction to be positive.

       Using Newton's law of motion, we can write :

                                             R\ -\ mg\ =\ ma

or                                          R\ -\ 70(10)\ =\ 70(5)

or                                          R\ =\ 350 +\ 700\ =\ 1050\ N

Thus the reading of the weighing scale will be :

                                                                               =\ \frac{R}{g}\ =\ \frac{1050}{10}\ =\ 105\ Kg

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support