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  • A mass of 5 kg is moving along a circular path of radius 1 m. If the mass moves with 300 revolutions per minute, its kinetic energy would be (a) 250 π2

A mass of 5 kg is moving along a circular path of radius 1 m. If the mass moves with 300 revolutions per minute, its kinetic energy would be
(a) 250 \pi ^{2}
(b) 100 \pi ^{2}
(c) 5 \pi ^{2}
(d) 0

Answers (1)

The answer is the option (a)

m = 5kg, radius = 1m, f = frequency of revolution = 300 rev/min = 300/60 rev/second

angular velocity = 2\pi f = \frac{(300\times 2\times \pi )}{60} = 10\pirad/second

now v = \omega R=10\pi\times1= 10\pi m/s

kinetic energy

= \frac{1}{2}mv^{2}

= \frac{1}{2}\times 5 \times 10\pi \times 10\pi = 250 \pi^{2} J

Posted by

infoexpert24

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