Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Two identical ball bearings in contact with each other and resting on a frictionless table are hit head-on by another ball bearing of the same mass moving initially with a speed V as shown in Figure.

Two identical ball bearings in contact with each other and resting on a frictionless table are hit head-on by another ball bearing of the same mass moving initially with a speed V as shown in Figure.

If the collision is elastic, which of the following (Figure) is a possible result after collision?

 

Answers (1)

In an elastic collision, the velocities of particles are interchanged while the kinetic energy and total linear momentum are conserved.

Kinetic energy before collision:

\frac{1}{2} mv^{2} + 0 = \frac{1}{2} mv^{2}

Option a) Kinetic energy after the collision:

Ka = \frac{1}{2} (2m) \left ( \frac{v}{2} \right )^{2} = \frac{1}{4} mv^{2}

Option b) Kinetic energy after the collision:

  Ka = \frac{1}{2} (m) \left ( v\right )^{2} = \frac{1}{2} mv^{2}

Option c) Kinetic energy after the collision:

Ka = \frac{1}{2} (3m) \left ( \frac{v}{3}\right )^{2} = \frac{1}{6} mv^{2}

Option d) Kinetic energy after the collision:

\\K_{a}=\frac{1}{2}mv^2+\frac{1}{2}m(\frac{v}{2})^2+\frac{1}{2}m(\frac{v}{3})^2\\\\=\frac{49}{72}mv^2

Hence, option b is correct.

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question