Q

# A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10-2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint

Q19  A mild steel wire of length 1.0 m and cross-sectional area   is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.

Views Let the ends of the steel wire be called A and B.

length of the wire is 2l = 1 m.

The cross-sectional area of the wire is

Let the depression at the midpoint due to the suspended 100 g be y.

Change in the length of the wire is

The strain is

The vertical components of the tension in the arms balance the weight of the suspended mass, we have

The stress in the wire will be

The Young's Modulus of steel is

The depression at the mid-point of the steel wire will be 1.074 cm.

Exams
Articles
Questions